The conductivity of a saturated solution of a sparingly soluble salt AB at 298 K is $1.85 \times 10^{-5} \, \text{S m}^{-1}$. The solubility product of the salt AB at 298 K is

Question

$1.32 \times 10^{-12}$

$1.74 \times 10^{-12}$

$5.7 \times 10^{-12}$

$7.5 \times 10^{-12}$

Solution

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