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Question

A correct statement is:

$[MnBr_4]^{2-}$ is tetrahedral.

$[Ni(NH_3)_6]^{2+}$ is an inner orbital complex.

$[Co(NH_3)_6]^{2+}$ is paramagnetic.

$[CoBr_2(en)_2]^-$ exhibits linkage isomerism.

Solution

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