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Question

The volume occupied by a single $CsCl$ ion pair in a crystal is $7.014 \times 10^{-23} \text{cm}^3$. The smallest Cs–Cs internuclear distance is equal to the length of the side of the cube corresponding to the volume of one $CsCl$ ion pair. The smallest Cs–Cs internuclear distance is nearly

$4.3 \text{Å}$

$4.5 \text{Å}$

$4.4 \text{Å}$

$4 \text{Å}$

Solution

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