Question
A plot of $\ln k$ vs. $\frac{1}{T}$ for a reaction gives a slope of $-1 \times 10^4$ K. The energy of activation for the reaction is
A plot of $\ln k$ vs. $\frac{1}{T}$ for a reaction gives a slope of $-1 \times 10^4$ K. The energy of activation for the reaction is