3A → 2B. The rate of reaction, \($\frac{d[B]}{dt}\), is equal to:
$-\frac{3}{2} \frac{d[A]}{dt}$
$-\frac{2}{3} \frac{d[A]}{dt}$
+$2 \frac{d[A]}{dt}$
$-\frac{1}{3} \frac{d[A]}{dt}$
Please login to view the detailed solution steps...
Subject Backlinks
Quiz Backlink
Related Question Backlinks
