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Question

For the reaction $\frac{1}{2} A \rightarrow 2B$, the rate of disappearance of A is related to the rate of appearance of B by the expression

$-\frac{d[A]}{dt} = 4 \frac{d[B]}{dt}$

$-\frac{d[A]}{dt} = \frac{1}{4} \frac{d[B]}{dt}$

$-\frac{d[A]}{dt} = \frac{1}{2} \frac{d[B]}{dt}$

$-\frac{d[A]}{dt} = \frac{1}{4} \frac{d[B]}{dt}$

Solution

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