When a brown compound of Mn (A) is treated with HCl, it gives a gas (B). The gas (B) taken in excess reacts with $NH_3$ to give an explosive compound (C). The compounds A, B, and C are:

Question

$A = MnO_2, B = Cl_2, C = NCl_3$

$A = MnO, B = Cl_2, C = NH_4Cl$

$A = Mn_3O_4, B = Cl_2, C = NCl_3$

$A = MnO_3, B = Cl_2, C = NCl_2$

Solution

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