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Question

The energy of an electron in the $n^{\text{th}}$ Bohr orbit of a hydrogen atom is

-$\frac{13.6}{n^{2}}$ eV

-$\frac{13.6}{n}$ eV

-$\frac{13.6}{n^{4}}$ eV

-$\frac{13.6}{n^{2}}$ eV

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