The number of atoms in 2.4 g of a body-centered cubic crystal with an edge length of 200 pm is (density = 10 g/cm3, $N_A = 6 \times 10^{23}$ atoms/mol).

Question

The number of atoms in 2.4 g of a body-centered cubic crystal with an edge length of 200 pm is (density = 10 g/cm³, $N_A = 6 \times 10^{23}$ atoms/mol).

$6 \times 10^{20}$

$6 \times 10^{22}$

$6 \times 10^{19}$

$6 \times 10^{23}$

Solution

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