The bond angle in $PH_4^+$ is greater than that of $PH_3$. This is because:

Question

$PH_3$ has a planar trigonal structure.

The hybridisation of P changes when $PH_3$ is converted to $PH_4^+$.

Lone pair-bond pair repulsion exists in $PH_3$.

$PH_4^+$ has a square planar structure.

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