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Question

Given $E^0_{\text{Fe}^{3+}/\text{Fe}^{2+}} = +0.76 \, \text{V}$ and $E^0_{\text{I}_2/\text{I}^-} = +0.55 \, \text{V}$, the equilibrium constant for the reaction taking place in the galvanic cell consisting of the above two electrodes is: $\frac{2.303RT}{F} = 0.06$.

$3 \times 10^8$

$5 \times 10^{12}$

$1 \times 10^7$

$1 \times 10^7$

Solution

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