Consider the following electrodes: P = Zn$^{2+}$ (0.0001 M)/Zn Q = Zn$^{2+}$ (0.1 M)/Zn R = Zn$^{2+}$ (0.01 M)/Zn S = Zn$^{2+}$ (0.001 M)/Zn $E^{\circ}_{\text{Zn}/\text{Zn}^{2+}} = -0.76~\text{V}$ The electrode potentials of the above electrodes in volts are in the order:

Question

Consider the following electrodes:
P = Zn$^{2+}$ (0.0001 M)/Zn
Q = Zn$^{2+}$ (0.1 M)/Zn
R = Zn$^{2+}$ (0.01 M)/Zn
S = Zn$^{2+}$ (0.001 M)/Zn
$E^{\circ}_{\text{Zn}/\text{Zn}^{2+}} = -0.76~\text{V}$
The electrode potentials of the above electrodes in volts are in the order:

P > S > R > Q

S > R > Q > P

Q > R > S > P

P > Q > R > S

Solution

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