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Question

If the rate constant for a first-order reaction is $k$, the time ($t$) required for the completion of 99\% of the reaction is given by:

$t = \frac{4.606}{k}$

$t = \frac{2.303}{k}$

$t = \frac{0.693}{k}$

$t = \frac{6.909}{k}$

Solution

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