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Question

A body is projected vertically upwards. The times taken to reach height $h$ while ascending and descending are $t_1$ and $t_2$ respectively. Then, the velocity of projection is (where $g$ is the acceleration due to gravity).

\(g\left(\sqrt{t_1 t_2}\right)\)

\(g \frac{t_1 t_2}{t_1 + t_2} \)

\(g \frac{\sqrt{t_1 t_2}}{2} \)

\(g\left(\frac{t_1 + t_2}{2}\right) \)

Solution

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