A ray of light is incident on the surface of a glass slab at an angle of 45°. If the lateral shift produced per unit thickness is $ \frac{1}{\sqrt{3}} $ m, the angle of refraction produced is:

Question

$\tan^{-1}\left(1 - \frac{2}{\sqrt{3}}\right)$

$\sin^{-1}\left(1 - \frac{2}{\sqrt{3}}\right)$

$\tan^{-1}\left(\frac{2}{\sqrt{3} - 1}\right)$

$\tan^{-1}\left(\frac{\sqrt{3}}{2}\right)$

Solution

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