A small oil drop of mass $10^{-6}$ kg is hanging and at rest between two plates separated by 1 mm, having a potential difference of 500 V. The acceleration due to gravity is $g = 10 \, \text{m/s}^{2}$.

Question

$2 \times 10^{-9}$ C

$2 \times 10^{-11}$ C

$2 \times 10^{-6}$ C

$2 \times 10^{-8}$ C

Solution

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