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Question

The height \( y \) and the distance \( x \) along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by $y = 8t - 5t^2$ meters and $x = 6t$ meters, where \( t \) is in seconds. The velocity with which the projectile is projected is

6 m s-1

8 m s-1

10 m s-1

14 m s-1

Solution

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