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Question

A solid sphere of mass $m$ rolls down an inclined plane without slipping, starting from rest at the top of the inclined plane. The linear speed of the sphere at the bottom of the inclined plane is $v$. The kinetic energy of the sphere at the bottom is ............

$\frac{1}{2}mv^2$

$\frac{5}{3}mv^2$

$\frac{2}{5}mv^2$

$\frac{7}{10}mv^2$

Solution

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