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Question

The critical angle of a certain medium is $\sin^{-1}\left(\frac{3}{5}\right)$. The polarizing angle of the medium is ...

$\sin^{-1}\left(\frac{4}{5}\right)$

$\tan^{-1}\left(\frac{5}{3}\right)$

$\tan^{-1}\left(\frac{3}{4}\right)$

$\tan^{-1}\left(\frac{4}{3}\right)$

Solution

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