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Question

If $\vec{A} = 2\hat{i} + 3\hat{j} + 8\hat{k}$ is perpendicular to $\vec{B} = 4\hat{i} + 4\hat{j} + a\hat{k}$, then the value of $a$ is.

$\frac{1}{2}$

$\frac{5}{2}$

1

-1

Solution

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