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Question

Two point charges, A = +3 nC and B = +1 nC, are placed 5 cm apart in the air. The work done to move charge B towards charge A by 1 cm is:

$1.35 \times 10^{-7} \, \text{J}$

$2.7 \times 10^{-7} \, \text{J}$

$2.0 \times 10^{-7} \, \text{J}$

$12.1 \times 10^{-7} \, \text{J}$

Solution

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