Two cells of emf \(E_1\) and \(E_2\) are joined in opposition (such that \(E_1 > E_2\)). If \(r_1\) and \(r_2\) are the internal resistances and \(R\) is the external resistance, then the terminal potential difference is

Question

\(\frac{E_1 + E_2}{r_1 + r_2} \times R\)

\(\frac{E_1 + E_2}{r_1 + r_2 + R} \times R\)

\(\frac{E_1 - E_2}{r_1 + r_2} \times R\)

\(\frac{E_1 - E_2}{r_1 + r_2 + R} \times R\)

Solution

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