If there is no torsion in the suspension thread, then the time period of a magnet executing SHM is

Question

$T = \frac{1}{2\pi} \sqrt{MB}$

$T = \frac{1}{2\pi} \sqrt{\frac{1}{MB}}$

$T = 2\pi \sqrt{\frac{1}{MB}}$

$T = 2\pi \sqrt{MB}$

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