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Question

A 100 W bulb is connected to an AC source of 220 V, 50 Hz. Then the current flowing through the bulb is:

$(\frac{5}{11} \text{ A})$

$(\frac{1}{2} \text{ A})$

$(2 \text{ A})$

$(\frac{3}{4} \text{ A})$

Solution

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