Two bodies, each of mass 8 kg, are placed at the vertices A and B of an equilateral triangle ABC. A third body, of mass 2 kg, is placed at the centroid G of the triangle. If AG = BG = CG = 1 m, where should a fourth body, of mass 4 kg, be placed so that the resultant force on the 2 kg body is zero?

Question

At C

At a point P on the line CG such that PG = $\frac{1}{\sqrt{2}}$ m

At a point P on the line CG such that PG = 0.5 m

At a point P on the line CG such that PG = 2 m

Solution

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