A copper rod AB of length $l$ is rotated about end A with a constant angular velocity $\omega$. The electric field at a distance $x$ from the axis of rotation is:

Question

$\frac{m \omega^2 x}{e}$

$\frac{e}{m \omega x}$

$\frac{e l}{m x}$

$\frac{\omega^2 l}{m e}$

Solution

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