The DC common-emitter current gain of an NPN transistor is 50. The potential difference applied across the collector and emitter of a transistor used in the CE configuration is $V_{CE} = 2 \, \text{V}$. If the collector resistance $R_C = 4 \, \text{k}\Omega$, then the base current ($I_B$) and the collector current ($I_C$) are:

Question

$I_B = 10 \, \mu\text{A}$

$I_B = 0.5 \, \mu\text{A}$

$I_B = 5 \, \mu\text{A}$

$I_B = 1 \, \mu\text{A}$

Solution

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