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Question

A space station is at a height equal to the radius of the Earth. If $V_E$ is the escape velocity on the surface of the Earth, then the escape velocity on the space station is _____ times $V_E$.

$\frac{1}{2}$

$\frac{1}{4}$

$\frac{1}{\sqrt{2}}$

$\frac{1}{\sqrt{3}}$

Solution

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