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Question

The energy of an electron in the second orbit of the hydrogen atom is $E_2$. The energy of the electron in the third orbit of $He^{+}$ will be?

$\frac{9}{16} E_2$

$\frac{16}{9} E_2$

$\frac{3}{16} E_2$

$\frac{16}{3} E_2$

Solution

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