The electric field lines on the left have twice the separation of those on the right, as shown in the figure. If the magnitude of the field at A is $40 \, \text{V/m}$, what is the force on a $20 \, \mu\text{C}$ charge kept at B?

Question

$1 \times 10^{-4} \, \text{V/m}$

$4 \times 10^{-4} \, \text{V/m}$

$8 \times 10^{-4} \, \text{V/m}$

$16 \times 10^{-4} \, \text{V/m}$

Solution

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