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Question

In the given figure, the magnetic field at ‘O’ is:

$\frac{3\mu_0 I}{8r} - \frac{\mu_0 I}{4\pi}$

$\frac{3\mu_0 I}{4r} + \frac{\mu_0 I}{4\pi}$

$\frac{3\mu_0 I}{10r} - \frac{\mu_0 I}{4\pi}$

$\frac{3\mu_0 I}{8r} + \frac{\mu_0 I}{4\pi}$

Solution

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