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Question

A fringe width of a certain interference pattern is $\beta = 0.002 \, \text{cm}$. What is the distance of the fifth dark fringe from the center?

$1 \times 10^{-2} \, \text{cm}$

$11 \times 10^{-2} \, \text{cm}$

$1.1 \times 10^{-2} \, \text{cm}$

$33 \times 10^{6} \, \text{cm}$

Solution

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