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Question
The point (5, -7) lies outside the circle.
$x^2 + y^2 - 8x = 0$
$x^2 + y^2 - 5x + 7y = 0$
$x^2 + y^2 - 5x + 7y - 1 = 0$
$x^2 + y^2 - 8x + 7y - 2 = 0$

Solution

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