The angles of elevation of the top of a TV tower from three points A, B, and C along a straight line through the foot of the tower are $\alpha$, $2\alpha$, and $3\alpha$ respectively. If AB = a, then the height of the tower is

Question

$a \tan \alpha$

$a \sin \alpha$

$a \sin 2\alpha$

$a \sin 3\alpha$

Solution

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