\(\int \frac{\sin^2 x \cos x}{\sqrt{1 - \sin^4 x}} \, dx =\)
\(\frac{1}{2} \sin^{-1}(\sin^2 x) + C\)
\(\frac{1}{2} \cos^{-1}(\sin^2 x) + C\)
\(\tan^{-1}(\sin^2 x) + C\)
\(\tan^{-1}(2 \sin x) + C\)
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