Question
If $A$ and $B$ are square matrices of the same order such that $(A+B)(A-B) = A^2 \cdot B^2$, then \((ABA^{-1})^2 =\)
If $A$ and $B$ are square matrices of the same order such that $(A+B)(A-B) = A^2 \cdot B^2$, then \((ABA^{-1})^2 =\)