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Question

If the sum $1 + \sin x + \sin^2 x + \ldots$ up to infinity equals $4 + 2\sqrt{3}$, and $x \neq \frac{\pi}{2}$, then $x =$

$\frac{\pi}{6}$

$\frac{\pi}{3}$

$\frac{2\pi}{3}$

$\frac{\pi}{2}$

Solution

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