If $f(x) = \int_{-1}^{x} |t| \, dt$, then for any $x \geq 0$, $f(x) =$

Question

$\frac{1}{2}(1 - x^2)$

$1 - x^2$

$\frac{1}{2}(1 + x^2)$

$1 + x^2$

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