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Question

$ \lim_{n \to \infty} \left\{ n \sin\left( \frac{2\pi n}{3n} \right) \cos\left( \frac{2\pi}{3n} \right) \right\} = \ldots $

1

$ \frac{\pi}{3} $

$ \frac{\pi}{6} $

$ \frac{2\pi}{3} $

Solution

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