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Question

If $a > b > 0$, $\sec^{-1}\left(\frac{a+b}{a-b}\right) = 2\sin^{-1}x$, then $x = \ldots$

$\sqrt{\frac{a}{a+b}}$

$\sqrt{\frac{a}{a+b}}$

$\sqrt{\frac{b}{a+b}}$

$\sqrt{\frac{b}{a+b}}$

Solution

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