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Question

The derivative of $e^{ax} \cos bx$ with respect to $x$ is $r e^{ax} \cos \left( bx + \tan^{-1} \frac{b}{a} \right)$. When $a > 0$ and $b > 0$, the value of $r$ is ...

$ab$

$a + b$

$\sqrt{a^2 + b^2}$

$\frac{1}{\sqrt{ab}}$

Solution

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