If $x = a \cos^3 \theta$ and $y = a \sin^3 \theta$, then $\frac{dy}{dx} = \ldots$
$\frac{a \sqrt{x}}{y}$
$-\frac{a \sqrt{y}}{x}$
$\frac{a \sqrt{y}}{x}$
$-\sqrt[3]{\frac{y}{x}}$
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