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Question

Equation of the circle centered at (4, 3) that touches the circle $x^2 + y^2 = 1$ externally is:

$x^2 + y^2 + 8x - 6y + 9 = 0$

$x^2 + y^2 - 8x + 6y + 9 = 0$

$x^2 + y^2 - 8x - 6y + 9 = 0$

$x^2 + y^2 + 8x + 6y + 9 = 0$

Solution

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