Equation of the circle centered at (4, 3) that touches the circle $x^2 + y^2 = 1$ externally is:
$x^2 + y^2 + 8x - 6y + 9 = 0$
$x^2 + y^2 - 8x + 6y + 9 = 0$
$x^2 + y^2 - 8x - 6y + 9 = 0$
$x^2 + y^2 + 8x + 6y + 9 = 0$
Please login to view the detailed solution steps...
Subject Backlinks
Quiz Backlink
Related Question Backlinks