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Question

 \(\text{The area bounded by the curve } y = \begin{cases} x^2 & \text{if } x < 0 \\ x & \text{if } x \geq 0 \end{cases} \text{ and the line } y = 4 \text{ is} \) 

$\frac{40}{3}$

$\frac{16}{3}$

$\frac{32}{3}$

$\frac{8}{3}$

Solution

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