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Question

The sum of the first $n$ terms of $\frac{1^2}{1} + \frac{1^2 + 2^2}{1 + 2} + \frac{1^2 + 2^2 + 3^2}{1 + 2 + 3} + \ldots$ is...

$\frac{n^2 - 2n}{3}$

$\frac{2n^2 + n}{3}$

$\frac{n(n + 2)}{3}$

$\frac{2n^2 - n}{3}$

Solution

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