In any triangle ABC, the simplified form of $\frac{\cos 2A}{a^2} - \frac{\cos 2B}{b^2}$ is ...

Question

$a^2 - b^2$

$\frac{1}{a^2 - b^2}$

$\frac{1}{a^2} - \frac{1}{b^2}$

$a^2 + b^2$

Please login to view the detailed solution steps...