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Question

Area of the triangle formed by the tangent and normal to the curve $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$ at $P\left(\frac{a}{\sqrt{2}}, \frac{b}{\sqrt{2}}\right)$ with the x-axis is ......

$4ab$

$\frac{ab\sqrt{a^2 + b^2}}{4}$

$\frac{4ab\sqrt{a^2 - b^2}}{4}$

$\frac{b(a^2 + b^2)}{4a}$

Solution

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