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Question

A sphere increases its volume at the rate of $\pi \text{ cm}^3/\text{s}$. The rate at which its surface area increases when the radius is $1$ cm is ___________?

$2\pi$ $\text{cm}^2/\text{s}$

$\pi$ $\text{cm}^2/\text{s}$

$\frac{3\pi}{2}$ $\text{cm}^2/\text{s}$

$\frac{\pi}{2}$ $\text{cm}^2/\text{s}$

Solution

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