When $x > 0$, then $ \int \cos^{-1} \left( \frac{1 - x^2}{1 + x^2} \right) \, dx $ is ...

Question

$2\left[x \tan^{-1}x - \log(1 + x^2)\right] + C$

$2\left[x \tan^{-1}x + \log(1 + x^2)\right] + C$

$2x \tan^{-1}x + \log(1 + x^2) + C$

$2x \tan^{-1}x - \log(1 + x^2) + C$

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