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Question

If $x \cos \alpha + y \sin \alpha = 4$ is tangent to $\frac{x^2}{25} + \frac{y^2}{9} = 1$, then the value of $\alpha$ is...

$\tan^{-1}\left(\frac{3}{7}\right)$

$\tan^{-1}\left(\sqrt{\frac{3}{7}}\right)$

$\tan^{-1}\left(\frac{7}{3}\right)$

$\tan^{-1}\left(\frac{3}{\sqrt{7}}\right)$

Solution

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